Why no destructing in def form?

Question

In a let form (Clojure here) I can doing something like

(let [[u s v] (svd A)] 
   (do-something-with u v))

where svd

Answer 1

def is basically the constructor for Vars. The first argument is the symbol that names the Var. It takes that symbol and returns a Var for that symbol. Destructuring would change these semantics.

You could write a macro that does it, though.