TypeScript: error when using parseInt() on a number

Question

The JavaScript function parseInt can be used to force conversion of a given parameter to an integer, whether that parameter is a string, float number, number, etc.

Answer 1

Don't use parseInt to do this operation -- use Math.floor.

Using parseInt to floor a number is not always going to yield correct results. parseInt(4e21) returns 4, not 4e21. parseInt(-0) returns 0, not -0.