Java 8 partition list

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一个人的身影
一个人的身影 2021-02-18 15:37

Is it possible to partition a List in pure Jdk8 into equal chunks (sublists).

I know it is possible using Guava Lists class, but can we do it with pure Jdk? I don\'t wan

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  •  自闭症患者
    2021-02-18 15:51

    private final String dataSheet = "103343262,6478342944, 103426540,84528784843, 103278808,263716791426, 103426733,27736529279, 
    103426000,27718159078, 103218982,19855201547, 103427376,27717278645, 
    103243034,81667273413";
    
        final int chunk = 2;
        AtomicInteger counter = new AtomicInteger();
        Collection> chuncks= Arrays.stream(dataSheet.split(","))
                .map(String::trim)
                .collect(Collectors.groupingBy(i->counter.getAndIncrement()/chunk))
                .values();
    

    result:

    pairs =
     "103218982" -> "19855201547"
     "103278808" -> "263716791426"
     "103243034" -> "81667273413"
     "103426733" -> "27736529279"
     "103426540" -> "84528784843"
     "103427376" -> "27717278645"
     "103426000" -> "27718159078"
     "103343262" -> "6478342944"
    

    We need to group each 2 elements into key, value pairs, so will partion the list into chunks of 2, (counter.getAndIncrement() / 2) will result same number each 2 hits ex:

    IntStream.range(0,6).forEach((i)->System.out.println(counter.getAndIncrement()/2));
    prints:
    0
    0
    1
    1
    2
    2
    

    You may ajust chunk sizee to partition lists sizes.

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