Generate random uint

Question

I need to generate random numbers with range for byte, ushort, sbyte, short, int, and uint. I am ab

Answer 1

Set the Range, " uint u0 <= returned value <= uint u1 ", using System.Random

It is easier to start with a range from "zero" (inclusive) to "u" (inclusive).
You might take a look at my other answer. If you are interested in a faster/more efficient way:
Uniform pseudo random numbers in a range. (It is quite a lot of code/text).

Below "rnd32(uint u)" returns: 0 <= value <= u .
The most difficult case is: "u = int.MaxValue". Then the chance that the first iteration of the "do-loops"
(a single iteration of both the outer and the inner "do-loop"), returns a valid value is 50%.
After two iterations, the chance is 75%, etc.

The chance is small that the outer "do-loop" iterates more than one time.
In the case of "u = int.MaxValue": 0%.

It is obvious that: "rnd32(uint u0, uint u1)" returns a value between u0 (incl) and u1 (incl).

private static Random rand = new Random();

private static uint rnd32(uint u)                                 //  0 <= x <= u
{
    uint x;
    if (u < int.MaxValue) return (uint)rand.Next((int)u + 1);
    do                                         
    {
        do x = (uint)rand.Next(1 << 30) << 2;
        while (x > u);
        x |= (uint)rand.Next(1 << 2);
    }
    while (x > u);
    return x;
}

private static uint rnd32(uint u0, uint u1)                      // set the range
{
    return u0 < u1 ? u0 + rnd32(u1 - u0) : u1 + rnd32(u0 - u1);
}