How to convert an integer to hexadecimal without the extra '0x' leading and 'L' trailing characters in Python?

Question

I am trying to convert big integer number to hexadecimal, but in result I get extra \"0x\" in the beginning and \"L\" at the and. Is there any way to remove them. Thanks. The nu

Answer 1

A more elegant way would be

hex(_number)[2:-1]

but you have to be careful if you're working with gmpy mpz types, then the 'L' doesn't exist at the end and you can just use

hex(mpz(_number))[2:]