How to convert an integer to hexadecimal without the extra '0x' leading and 'L' trailing characters in Python?

Question

I am trying to convert big integer number to hexadecimal, but in result I get extra \"0x\" in the beginning and \"L\" at the and. Is there any way to remove them. Thanks. The nu

Answer 1

Be careful when using the accepted answer as lstrip('0x') will also remove any leading zeros, which may not be what you want, see below:

>>> account = '0x000067'
>>> account.lstrip('0x')
'67'
>>>

If you are sure that the '0x' prefix will always be there, it can be removed simply as follows:

>>> hex(42)
'0x2a'
>>> hex(42)[2:]
'2a'
>>>

[2:] will get every character in the string except for the first two.