How to convert an integer to hexadecimal without the extra '0x' leading and 'L' trailing characters in Python?

Question

I am trying to convert big integer number to hexadecimal, but in result I get extra \"0x\" in the beginning and \"L\" at the and. Is there any way to remove them. Thanks. The nu

Answer 1

Similar to Praveen's answer, you can also directly use built-in format().

>>> a = 44199528911754184119951207843369973680110397
>>> format(a, 'x')
'1fb62bdc9e54b041e61857943271b44aafb3d'