How to convert an integer to hexadecimal without the extra '0x' leading and 'L' trailing characters in Python?

Question

I am trying to convert big integer number to hexadecimal, but in result I get extra \"0x\" in the beginning and \"L\" at the and. Is there any way to remove them. Thanks. The nu

Answer 1

The 0x is literal representation of hex numbers. And L at the end means it is a Long integer.

If you just want a hex representation of the number as a string without 0x and L, you can use string formatting with %x.

>>> a = 44199528911754184119951207843369973680110397
>>> hex(a)
'0x1fb62bdc9e54b041e61857943271b44aafb3dL'
>>> b = '%x' % a
>>> b
'1fb62bdc9e54b041e61857943271b44aafb3d'