C++ Overloading Conversion Operators

Question

I am trying to have a class that allows implicit casting to certain built in types, like unsigned long int and since I\'m trying to do this as correct as possible (this is my fi

Answer 1

You could remove the const from the declaration, but what you almost certainly want to do is add it to the definition:

CustomizedInt::operator unsigned long() const
{
    unsigned long int output;
    output = (unsigned long int)data;
    return output;
}