How to pass parameters with `include`?

Question

I have a PHP script called customers.php that is passed a parameter via the URL, e.g.:

http://www.mysite,com/customers.php?employeeId=1

Inside my customers.php s

Answer 1

You can use $GLOBALS to solve this issue as well.

 $tit = "Hello";

 $GLOBALS["docTitle"] =  $tit;

 include ("my.php");