Iterating over an odd (even) elements only in a range-based loop

Question

Suppose we have a plain array (or other container which support range based loops):

const int N = 8;
int arr[N] = {0, 1, 2, 3, 4, 5, 6, 7};

Usi

Answer 1

This isn't really an answer to the question, but—for what it is worth—whenever I run into a limitation of ranged-for, I look for a standard algorithm solution. Like...

#include 
#include 
#include 
#include 

int main()
{
    int arr[] {0, 1, 2, 3, 4, 5, 6, 7};
    std::copy_if(
        std::begin(arr), std::end(arr),
        std::ostream_iterator(std::cout, "\n"),
        [is_odd_element = true](int n) mutable {
            return std::exchange(is_odd_element, not is_odd_element);
        });
}