How to use field name or column header in openpyxl?

Question

See my code below. This code works very well, but I would like to do two things. One thing is I made if statement with or much shorter than actual for example. I have many colum

Answer 1

EDIT

Assuming these are the header names you are looking for:

colnames = ['Header1', 'Header2', 'Header3']

Find the indices for these columns:

col_indices = {n for n, cell in enumerate(sheet.rows[0]) if cell.value in colnames}

Now iterate over the remain rows:

for row in sheet.rows[1:]:
    for index, cell in enumerate(row):
         if index in col_indices:
             if cell.value.upper() == 'OldValue1':
                  cell.value = 1
                  print(cell.value)
             elif cell.value.upper() == 'OldValue2':
                 cell.value = 2
                 print(cell.value)

Use a dictionary instead of a set to keep the column names around:

col_indices = {n: cell.value for n, cell in enumerate(sheet.rows[0]) 
               if cell.value in colnames}

for row in sheet.rows[1:]:
    for index, cell in enumerate(row):
        if index in col_indices:
            print('col: {}, row: {}, content: {}'.format(
                   col_indices[index], index, cell.value))
            if cell.value.upper() == 'OldValue1':
                 cell.value = 1
            elif cell.value.upper() == 'OldValue2':
                 cell.value = 2

Old answer

This makes your if statement shorter:

if cellObj.column in 'HILM':
    print(cellObj.value),

For multi letter column coordinates you need to use a list:

if cellObj.column in ['H', 'AA', 'AB', 'AD']:
    print(cellObj.value),