Template partial specialization for __stdcall function pointer

Question

typedef bool (*my_function_f)(int, double);
typedef bool (__stdcall *my_function_f2)(int, double);
//            ^^^^^^^^^

template class TFunction;

tem         


        

Answer 1

This is because (*) means default calling convention, which is __cdecl.

template
class TFunction
{
  typedef R (*func_type)(T0,T1);
};

is actually equal to

template
class TFunction
{
  typedef R (__cdecl *func_type)(T0,T1);
};

which, of course, will not match an R(__stdcall *)(T0, T1) on Win32 where __stdcall is not ignored. If you want to partially specialize for function pointers then you will need a partial spec for every calling convention you want to accept.