Template partial specialization for __stdcall function pointer

Question

typedef bool (*my_function_f)(int, double);
typedef bool (__stdcall *my_function_f2)(int, double);
//            ^^^^^^^^^

template class TFunction;

tem         


        

Answer 1

No, this is by design. The calling convention is very much part of the function declaration, your template function uses the default calling convention. Which is not __stdcall unless you compile with /Gz. The default is /Gd, __cdecl.

The code compiles when you target x64 because it blissfully has only one calling convention.

Fix:

template
class TFunction
{
    // etc..
};