How to 'wrap' two classes with identical methods?

Question

I have to handle two classes with identical methods but they don\'t implement the same interface, nor do they extend the same superclass. I\'m not able / not allowed to change t

Answer 1

There, a duck-typed solution. This will accept any object with valueOne, valueTwo properties and is trivially extensible to further props.

public class Wrapper
{
  private final Object wrapped;
  private final Map methods = new HashMap();
  public Wrapper(Object w) {
    wrapped = w;
    try {
      final Class c = w.getClass();
      for (String propName : new String[] { "ValueOne", "ValueTwo" }) {
        final String getter = "get" + propName, setter = "set" + propName;
        methods.put(getter, c.getMethod(getter));
        methods.put(setter, c.getMethod(setter, String.class));
      }
    } catch (Exception e) { throw new RuntimeException(e); }
  }
  public String getValueOne() {
    try { return (String)methods.get("getValueOne").invoke(wrapped); }
    catch (Exception e) { throw new RuntimeException(e); }
  }
  public void setValueOne(String v) {
    try { methods.get("setValueOne").invoke(wrapped, v); }
    catch (Exception e) { throw new RuntimeException(e); }
  }
  public String getValueTwo() {
    try { return (String)methods.get("getValueTwo").invoke(wrapped); }
    catch (Exception e) { throw new RuntimeException(e); }
  }
  public void setValueTwo(String v) {
    try { methods.get("setValueTwo").invoke(wrapped, v); }
    catch (Exception e) { throw new RuntimeException(e); }
  }
}