I have to handle two classes with identical methods but they don\'t implement the same interface, nor do they extend the same superclass. I\'m not able / not allowed to change t
You can use a dynamic proxy to create a "bridge" between an interface you define and the classes that conform but do not implement your interface.
It all starts with an interface:
interface Something {
public String getValueOne();
public void setValueOne(String valueOne);
public String getValueTwo();
public void setValueTwo(String valueTwo);
}
Now you need an InvocationHandler
, that will just forward calls to the method that matches the interface method called:
class ForwardInvocationHandler implements InvocationHandler {
private final Object wrapped;
public ForwardInvocationHandler(Object wrapped) {
this.wrapped = wrapped;
}
@Override
public Object invoke(Object proxy, Method method, Object[] args)
throws Throwable {
Method match = wrapped.getClass().getMethod(method.getName(), method.getParameterTypes());
return match.invoke(wrapped, args);
}
}
Then you can create your proxy (put it in a factory for easier usage):
SomethingA a = new SomethingA();
a.setValueOne("Um");
Something s = (Something)Proxy.newProxyInstance(
Something.class.getClassLoader(),
new Class[] { Something.class },
new ForwardInvocationHandler(a));
System.out.println(s.getValueOne()); // prints: Um
Another option is simpler but requires you to subclass each class and implement the created interface, simply like this:
class SomethingAImpl extends SomethingA implements Something {}
class SomethingBImpl extends SomethingB implements Something {}
(Note: you also need to create any non-default constructors)
Now use the subclasses instead of the superclasses, and refer to them through the interface:
Something o = new SomethingAImpl(); // o can also refer to a SomethingBImpl
o.setValueOne("Uno");
System.out.println(o.getValueOne()); // prints: Uno