Haskell: Multiple Case Statements in Single Function

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故里飘歌
故里飘歌 2021-02-15 09:58

I want to include more than one case statement in a Haskell function (see below for an example of a hypothetical function).

However, it is not legal Haskell. What is a b

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  •  说谎
    说谎 (楼主)
    2021-02-15 10:24

    In general the body of a function has to be a single expression (very often made up of smaller expressions). The following isn't allowed, for example:

    f x y =
      "foo"
      "bar"
    

    This is equivalent to your first example—we've just substituted one kind of expression (string literals) for another (your case expressions).

    It's certainly possible to include more than one case expression in a Haskell function:

    tester :: Int -> String -> (String, String)
    tester x y = (a, b)
      where
        a = case (x < 0) of  
              True -> "less than zero."  
              False -> "greater than or equal to zero."  
        b = case (y == "foo") of
              True -> "the name is foo."  
              False -> "the name is not foo."
    

    Or even:

    tester :: Int -> String -> IO ()
    tester x y = do
      putStrLn $ case (x < 0) of  
                   True -> "less than zero."  
                   False -> "greater than or equal to zero."  
      putStrLn $ case (y == "foo") of
                   True -> "the name is foo."  
                   False -> "the name is not foo."
    

    These work because the body of the function is a single expression (although neither is really idiomatic Haskell).

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