$x() function is not defined inside a Chrome extension, content script

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暗喜
暗喜 2021-02-15 03:44
$x(\"//a[contains(@href,\'.jpg\')]\");

works as expected from the developer tools command prompt. But, when in an extension\'s content-script I get a \

2条回答
  •  不思量自难忘°
    2021-02-15 04:43

    $x() is not part of the run-time environment of a web page or content script. It is a tool that is part of the Command Line API for Chrome's DevTools.

    To use XPath in a content script, you need to do it the normal way, the DevTools convenient shortcut is not available.

    Your code would look like this:

    var jpgLinks    = document.evaluate (
        "//a[contains(@href,'.jpg')]",
        document,
        null,
        XPathResult.ORDERED_NODE_SNAPSHOT_TYPE,
        null
    );
    var numLinks    = jpgLinks.snapshotLength;
    
    for (var J = 0;  J < numLinks;  ++J) {
        var thisLink = jpgLinks.snapshotItem (J);
        console.log ("Link ", J, " = ", thisLink);
    }
    

    -- which is the kind of thing that $x() was doing for you, behind the scenes.


    While you are at it, consider switching to CSS selectors. Then the same functionality is:

    var jpgLinks    = document.querySelectorAll ("a[href$='.jpg']");
    var numLinks    = jpgLinks.length;
    
    for (var J = 0;  J < numLinks;  ++J) {
        var thisLink = jpgLinks[J];
        console.log ("Link ", J, " = ", thisLink);
    }
    

    -- which is much more palatable in my book.

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