How do I get the x and y positions of an element in an AngularJS directive

Question

Within the link function part of a directive we have access to the element object. I wish to determine if the element object is within the current view

Answer 1

You can use element[0].getBoundingClientRect, it works - there is an example:

http://plnkr.co/edit/2eOw3B0MaM2vw3bQuFnf

If you need to track element visibility in angular directive, except scroll you also need to handle events: DOMContentLoaded, load and resize. Also it would be better to create only one handler for those events, and stop tracking element when directive is destroyed

app.directive('trackVisibility', function(){
  function isVisible(el) {
    var rect = el.getBoundingClientRect();
    var clw = (window.innerWidth || document.documentElement.clientWidth);
    var clh = (window.innerHeight || document.documentElement.clientHeight) ;

    // checks if element is fully visible
    //return (rect.top >= 0 && rect.bottom <= clh) && (rect.left >= 0 && rect.right <= clw);

    // checks if part of element is visible
    return (rect.left <= clw && 0 <= rect.right && rect.top <= clh && 0 <= rect.bottom);

  }
  var reg = [];

  function register(element, fn) {
    reg.push([element, fn]);
  }

  function deregister(element) {
    reg = angular.filter(reg, function (item) {
      return item[0] !== element;
    });
  }

  angular.element(window).on('DOMContentLoaded load resize scroll', function () {
    angular.forEach(reg, function (item) {
        item[1](isVisible(item[0]));
    });
  });

  return {
    restrict: 'A',
    link: function (scope, element, attrs, controller) {
      register(element[0], function(isVisible){
        scope.$apply(function(){
          scope.isVisible = isVisible;
        })
      });
      scope.$on('$destroy', function(){
        deregister(element);
      })
    }
  };
});

there is an example: http://plnkr.co/edit/VkCgBvGnCWZ0JCM8tlaJ

I have used this approach to dynamically load images when they become visible.