Retain precision with double in Java

Question

public class doublePrecision {
    public static void main(String[] args) {

        double total = 0;
        total += 5.6;
        total += 5.8;
        System.out         


        

Answer 1

Doubles are approximations of the decimal numbers in your Java source. You're seeing the consequence of the mismatch between the double (which is a binary-coded value) and your source (which is decimal-coded).

Java's producing the closest binary approximation. You can use the java.text.DecimalFormat to display a better-looking decimal value.