c/c++ left shift unsigned vs signed

Question

I have this code.

#include 

int main()
{
    unsigned long int i = 1U << 31;
    std::cout << i << std::endl;
    unsigned lon         


        

Answer 1

It's not "bizarre".

Try printing the number in hex and see if it's any more recognizable:

std::cout << std::hex << i << std::endl;

And always remember to qualify your literals with "U", "L" and/or "LL" as appropriate:

http://en.cppreference.com/w/cpp/language/integer_literal

unsigned long long l1 = 18446744073709550592ull;
unsigned long long l2 = 18'446'744'073'709'550'592llu;
unsigned long long l3 = 1844'6744'0737'0955'0592uLL;
unsigned long long l4 = 184467'440737'0'95505'92LLU;