Force typescript to put methods on the instance not the prototype

Question

Is it possible to force typescript to put methods on the instance not the prototype. I ask this because I frequently have \"this\" scope issues which having methods on the proto

Answer 1

The methods on the prototype are the methods that are available on each instance.

class Example {
    constructor(private someProperty: string) {

    }

    method() {
        return this.someProperty;
    }
}

var exampleA = new Example('A');
var exampleB = new Example('B');
var exampleC = new Example('C');

console.log(exampleA.method()); // A
console.log(exampleB.method()); // B
console.log(exampleC.method()); // C

Each instance will have the someProperty and method() copied to its prototype. You can check this using:

alert(exampleC.hasOwnProperty('someProperty') ? 'Yes' : 'No');

It is only when the instance doesn't have its own property that JavaScript will walk up any dependency chain to find the property on a class higher up the dependency chain.

If you supply the code where you are having trouble with the scope of this I'm sure we can help you to fix it.