Sum for multiple date ranges in a single call?

Question

I have the following query:

SELECT 
   SUM(\"balance_transactions\".\"fee\") AS sum_id 
   FROM \"balance_transactions\" 
   JOIN charges ON balance_transactions         


        

Answer 1

It hasn't been mentioned yet and would not be as efficient as a single select BUT as a solution you could use a UNION and group by your own static identifier (date range group) such as:

SELECT 
   'a' AS DateRangeIdentifier,
   SUM("balance_transactions"."fee") AS sum_id 
   FROM "balance_transactions" 
   JOIN charges ON balance_transactions.source = charges.balance_id 
   WHERE "balance_transactions"."account_id" = 6 
      AND (balance_transactions.type = 'charge' 
      AND charges.refunded = false 
      AND charges.invoice IS NOT NULL) 
      AND ("balance_transactions"."created" BETWEEN '2013-01-01' AND '2013-01-31')

UNION 

SELECT 
   'b' AS DateRangeIdentifier,
   SUM("balance_transactions"."fee") AS sum_id 
   FROM "balance_transactions" 
   JOIN charges ON balance_transactions.source = charges.balance_id 
   WHERE "balance_transactions"."account_id" = 6 
      AND (balance_transactions.type = 'charge' 
      AND charges.refunded = false 
      AND charges.invoice IS NOT NULL) 
      AND ("balance_transactions"."created" BETWEEN '2013-07-01' AND '2013-07-31')

UNION 

SELECT 
   'c' AS DateRangeIdentifier,
   SUM("balance_transactions"."fee") AS sum_id 
   FROM "balance_transactions" 
   JOIN charges ON balance_transactions.source = charges.balance_id 
   WHERE "balance_transactions"."account_id" = 6 
      AND (balance_transactions.type = 'charge' 
      AND charges.refunded = false 
      AND charges.invoice IS NOT NULL) 
      AND ("balance_transactions"."created" BETWEEN '2013-12-20' AND '2014-01-19')

GROUP BY DateRangeIdentifier, sum_id

This way would at least yield a single database request and not a loop in your code.

See updated Fiddle here: http://sqlfiddle.com/#!15/9ce0f/5