lightweight python library to query city/state name by zip code?

Question

Pretty simple here, I\'m looking for a lightweight library that will allow me to lookup a city/state pairing for a given zip code. I am using django FWIW. Thanks in advance.

Answer 1

Use this library uszipcode.

Advantages:

• Data is up-to-date, super rich info, way richer and more up-to-date than zipcode and pyzipcode and any other python zipcode library.
• Query is super easy, and there are like 20+ built-in query pattern you can use. And you can customize your query anyway you want.
• Support fuzzy string match for city and state. You don't need to use the exact name.

>>> from uszipcode import ZipcodeSearchEngine
>>> search = ZipcodeSearchEngine()
>>> zipcode = search.by_zipcode("10001")
>>> print(zipcode)
{
    "City": "New York", 
    "Density": 34035.48387096774, 
    "HouseOfUnits": 12476, 
    "LandArea": 0.62, 
    "Latitude": 40.75368539999999, 
    "Longitude": -73.9991637, 
    "NEBoundLatitude": 40.8282129, 
    "NEBoundLongitude": -73.9321059, 
    "Population": 21102, 
    "SWBoundLatitude": 40.743451, 
    "SWBoungLongitude": -74.00794499999998, 
    "State": "NY", 
    "TotalWages": 1031960117.0, 
    "WaterArea": 0.0, 
    "Wealthy": 48903.42702113544, 
    "Zipcode": "10001", 
    "ZipcodeType": "Standard"
}

# fuzzy city, state search, case insensitive, spelling mistake tolerant
# all zipcode in new york
>>> result = search.by_city_and_state(city="newyork", state="NY")
>>> search.export_to_csv(result, "result.csv")

Very easy to use to build advance search

>>> result = search.find(city="new york", 
... wealthy=100000, sort_by="Wealthy", ascending=False, returns=10)