Is there a more efficient way to find most common n-grams?

Question

I\'m trying to find k most common n-grams from a large corpus. I\'ve seen lots of places suggesting the naïve approach - simply scanning through the entire corpus and keeping a

Answer 1

In Python, using NLTK:

$ wget http://norvig.com/big.txt
$ python
>>> from collections import Counter
>>> from nltk import ngrams
>>> bigtxt = open('big.txt').read()
>>> ngram_counts = Counter(ngrams(bigtxt.split(), 2))
>>> ngram_counts.most_common(10)
[(('of', 'the'), 12422), (('in', 'the'), 5741), (('to', 'the'), 4333), (('and', 'the'), 3065), (('on', 'the'), 2214), (('at', 'the'), 1915), (('by', 'the'), 1863), (('from', 'the'), 1754), (('of', 'a'), 1700), (('with', 'the'), 1656)]

In Python, native (see Fast/Optimize N-gram implementations in python):

>>> import collections
>>> def ngrams(text, n=2):
...     return zip(*[text[i:] for i in range(n)])
>>> ngram_counts = collections.Counter(ngrams(bigtxt.split(), 2))
>>> ngram_counts.most_common(10)
    [(('of', 'the'), 12422), (('in', 'the'), 5741), (('to', 'the'), 4333), (('and', 'the'), 3065), (('on', 'the'), 2214), (('at', 'the'), 1915), (('by', 'the'), 1863), (('from', 'the'), 1754), (('of', 'a'), 1700), (('with', 'the'), 1656)]

In Julia, see Generate ngrams with Julia

import StatsBase: countmap
import Iterators: partition
bigtxt = readstring(open("big.txt"))
ngram_counts = countmap(collect(partition(split(bigtxt), 2, 1)))

Rough timing:

$ time python ngram-test.py # With NLTK.

real    0m3.166s
user    0m2.274s
sys 0m0.528s

$ time python ngram-native-test.py 

real    0m1.521s
user    0m1.317s
sys 0m0.145s

$ time julia ngram-test.jl 

real    0m3.573s
user    0m3.188s
sys 0m0.306s