How to use princomp () function in R when covariance matrix has zero's?

Question

While using princomp() function in R, the following error is encountered : \"covariance matrix is not non-negative definite\".

I think, this i

Answer 1

The first strategy might be to decrease the tolerance argument. Looks to me that princomp won't pass on a tolerance argument but that prcomp does accept a 'tol' argument. If not effective, this should identify vectors which have nearly-zero covariance:

nr0=0.001
which(abs(cov(M)) < nr0, arr.ind=TRUE)

And this would identify vectors with negative eigenvalues:

which(eigen(M)$values < 0)

Using the h9 example on the help(qr) page:

> which(abs(cov(h9)) < .001, arr.ind=TRUE)
      row col
 [1,]   9   4
 [2,]   8   5
 [3,]   9   5
 [4,]   7   6
 [5,]   8   6
 [6,]   9   6
 [7,]   6   7
 [8,]   7   7
 [9,]   8   7
[10,]   9   7
[11,]   5   8
[12,]   6   8
[13,]   7   8
[14,]   8   8
[15,]   9   8
[16,]   4   9
[17,]   5   9
[18,]   6   9
[19,]   7   9
[20,]   8   9
[21,]   9   9
> qr(h9[-9,-9])$rank  
[1] 7                  # rank deficient, at least at the default tolerance
> qr(h9[-(8:9),-(8:9)])$ take out only the vector  with the most dependencies
[1] 6                   #Still rank deficient
> qr(h9[-(7:9),-(7:9)])$rank
[1] 6

Another approach might be to use the alias function:

alias( lm( rnorm(NROW(dfrm)) ~ dfrm) )