How can I use lambda function within itself?

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花落未央
花落未央 2021-02-14 05:42

I have this code and don\'t know if what I would like to achieve is possible.

_acceptor.async_accept(
    _connections.back()->socket(),
    [this](const boos         


        
1条回答
  •  名媛妹妹
    2021-02-14 06:15

    You have to store a copy of the lambda in itself, using std::function<> (or something similar) as an intermediary:

    std::function func;
    func = [&func, this](const boost::system::error_code& ec)
    {
        _connections.push_back(std::make_shared(_acceptor.get_io_service()));
        _acceptor.async_accept(_connections.back()->socket(), func);
    }
    
    _acceptor.async_accept(_connections.back()->socket(), func);
    

    But you can only do it by reference; if you try to capture it by value, it won't work. This means you have to limit the usage of such a lambda to uses were capture-by-reference will make sense. So if you leave this scope before your async function is finished, it'll break.

    Your other alternative is to create a proper functor rather than a lambda. Ultimately, lambdas can't do everything.

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