Pandas: Change a specific column name in dataframe having multilevel columns

Question

I want to find the way change name of specific column in a multilevel dataframe.

With this data:

data = {
    (\'A\', \'1\', \'I\'): [1, 2, 3, 4, 5], 
           


        

Answer 1

This is my theory

pandas does not want pd.Indexs to be mutable. We can see this if we try to change the first element of the index ourselves

dataDF.columns[0] = ('Z', '100', 'Z')

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
 in ()
----> 1 dataDF.columns[0] = ('Z', '100', 'Z')

//anaconda/envs/3.5/lib/python3.5/site-packages/pandas/indexes/base.py in __setitem__(self, key, value)
   1372 
   1373     def __setitem__(self, key, value):
-> 1374         raise TypeError("Index does not support mutable operations")
   1375 
   1376     def __getitem__(self, key):

TypeError: Index does not support mutable operations

---

But pandas can't control what you do the values attribute.

dataDF.columns.values[0] = ('Z', '100', 'Z')

we see that dataDF.columns looks the same, but dataDF.columns.values clearly reflects the change. Unfortunately, df.columns.values isn't what shows up on the display of the dataframe.

---

On the other hand, this really does seem like it should work. The fact that it doesn't feels wrong to me.

dataDF.rename(columns={('A', '1', 'I'): ('Z', '100', 'Z')}, inplace=True)

I believe the reason this only works after having changed the values, is that rename is forcing the reconstruction of the columns by looking at the values. Since we change the values, it now works. This is exceptionally kludgy and I don't recommend building a process that relies on this.

---

my recommendation

• identify location of column name you want to change
• assign name of column to the array of values
• build new columns from scratch, explicity

---

from_col = ('A', '1', 'I')
to_col = ('Z', '100', 'Z')
colloc = dataDF.columns.get_loc(from_col)
cvals = dataDF.columns.values
cvals[colloc] = to_col

dataDF.columns = pd.MultiIndex.from_tuples(cvals.tolist())

dataDF

[![enter code here][1]][1]