Unwrap an Optional only if it is present

Question

So currently I have

String uri = website.getUri();
Optional pageDetail = webClient.getDetailOfUri(uri);
String displayName;
String description;         


        

Answer 1

Use Optional#orElseGet that takes a Supplier:

// Reference to the constructor, but you could use a Factory, etc.
// All you need is a method that returns a PageDetail
// See the Javadoc and http://www.byteslounge.com/tutorials/java-8-consumer-and-supplier
Supplier emptySupplier = PageDetail::new;

pageDetail = pageDetail.orElseGet(emptySupplier);
// works the same
//pageDetail = pageDetail.orElseGet(() -> new PageDetail());

String displayname = pageDetail.getName();
String uri = pageDetail.getUri();

orElseGet will create an empty PageDetail only if the Optional has a null value. This keeps your code resource efficient.

Editable/compilable sample : https://ideone.com/9h1Ntg

Edit: Thanks everybody for the feedback! I was actually adding orElseGet which I find better. I also fixed the code to unwrap the Optional so pageDetail ends being an actual PageDetail instance.

Edit 2: Added different syntax example and editable/compilable example.