Is it possible to multiplex several channels into one?

Question

The idea is to have a variable number of channels in a slice, push each value received through them into a single channel, and close this output channel once the last one of the

Answer 1

Using goroutines I produced this. Is it what you want ?

package main

import (
    "fmt"
)

func multiplex(cin []chan int, cout chan int) {
    n := len(cin)
    for _, ch := range cin {
        go func(src chan int) {
            for {
                v, ok := <-src
                if ok {
                    cout <- v
                } else {
                    n-- // a little dangerous. Maybe use a channel to avoid missed decrements
                    if n == 0 {
                        close(cout)
                    }
                    break
                }
            }
        }(ch)
    }
}

// a main to test the multiplex
func main() {
    cin := make([]chan int, 3)
    cin[0] = make(chan int, 2)
    cin[1] = make(chan int, 2)
    cin[2] = make(chan int, 2)
    cout := make(chan int, 2)
    multiplex(cin, cout)
    cin[1] <- 1
    cin[0] <- 2
    cin[2] <- 3
    cin[1] <- 4
    cin[0] <- 5
    close(cin[1])
    close(cin[0])
    close(cin[2])
    for {
        v, ok := <-cout
        if ok {
            fmt.Println(v)
        } else {
            break
        }
    }
}

EDIT : References :

http://golang.org/ref/spec#Receive_operator

http://golang.org/ref/spec#Close