Is there any efficient easy way to compare two lists with the same length with Mathematica?

Question

Given two lists A={a1,a2,a3,...an} and B={b1,b2,b3,...bn}, I would say A>=B if and only if all ai>=bi.

There is

Answer 1

When working with packed arrays and numeric comparator such as >= it would be hard to beat David's Method #1.

However, for more complicated tests that cannot be converted to simple arithmetic another method is required.

A good general method, especially for unpacked lists, is to use Inner:

Inner[test, a, b, And]

This does not make all of the comparisons ahead of time and can therefore be much more efficient in some cases than e.g. And @@ MapThread[test, {a, b}]. This illustrates the difference:

test = (Print[#, " >= ", #2]; # >= #2) &;

{a, b} = {{1, 2, 3, 4, 5}, {1, 3, 3, 4, 5}};

Inner[test, a, b, And]

1 >= 1
2 >= 3

False

And @@ MapThread[test, {a, b}]

1 >= 1
2 >= 3
3 >= 3
4 >= 4
5 >= 5

False

If the arrays are packed and especially if the likelihood that the return is False is high then a loop such as David's Method #2 is a good option. It may be better written:

Null === Do[If[a[[i]] ~test~ b[[i]], , Return@False], {i, Length@a}]

1 >= 1
2 >= 3

False