Bit hack: Expanding bits

Question

I am trying to convert a uint16_t input to a uint32_t bit mask. One bit in the input toggles two bits in the output bit mask. Here is an example conver

Answer 1

Here's a working implementation:

uint32_t remask(uint16_t x)
{
    uint32_t i;
    uint32_t result = 0;
    for (i=0;i<16;i++) {
        uint32_t mask = (uint32_t)x & (1U << i);
        result |= mask << (i);
        result |= mask << (i+1);
    }
    return result;
}

On each iteration of the loop, the bit in question from the uint16_t is masked out and stored.

That bit is then shifted by its bit position and ORed into the result, then shifted again by its bit position plus 1 and ORed into the result.