Stub out module function

Question

Edit: Being a little bit more precise.

I want to test usecases for a Github API wrapper extension, that our team has created. For testing, we don\'t want to use API wrap

Answer 1

I found that this worked for me...

const sinon          = require( 'sinon' );
const moduleFunction = require( 'moduleFunction' );

//    Required modules get added require.cache. 
//    The property name of the object containing the module in require.cache is 
//    the fully qualified path of the module e.g. '/Users/Bill/project/node_modules/moduleFunction/index.js'
//    You can get the fully qualified path of a module from require.resolve
//    The reference to the module itself is the exports property

const stubbedModule = sinon.stub( require.cache[ require.resolve( 'moduleFunction' ) ], 'exports', () => {

    //    this function will replace the module

    return 'I\'m stubbed!';
});

// sidenote - stubbedModule.default references the original module...

You have to make sure that you stub the module (as above) before it's required elsewhere...

// elsewhere...

const moduleFunction = require( 'moduleFunction' ); 

moduleFunction();    // returns 'I'm stubbed!'