Looking for which (if either) of the following ternary statement\'s syntax is compliant with PSR-2 - I
The PSR-2 standard specifically omits any opinion on operators:
There are many elements of style and practice intentionally omitted by this guide. These include but are not limited to: ... Operators and assignment
Since parentheses are used to group expressions, your example doesn't make much sense:
$error = ($error_status) ? 'Error' : 'No Error';
Here there is no meaning to surrounding a single variable in parentheses. A more complex condition might benefit from parentheses, but in most cases they would be for readability only.
A more common pattern would be to always surround the entire ternary expression:
$error = ($error_status ? 'Error' : 'No Error');
The main motivation for this is that the ternary operator in PHP has rather awkward associativity and precedence, so that using it in complex expressions often gives unexpected / unhelpful results.
A common case is string concatenation, e.g.:
$error = 'Status: ' . $error_status ? 'Error' : 'No Error';
Here the concatenation (.
operator) is actually evaluated before the ternary operator, so the condition is always a non-empty string (beginning 'Status: '
), and you will always get the string Error'
as the result.
Parentheses are necessary to prevent this:
$error = 'Status: ' . ($error_status ? 'Error' : 'No Error');
A similar situation exists when "stacking" ternary expressions to form the equivalent of an if-elseif chain, as a mistake early in PHP's history means multiple ternary operators are evaluated in sequence left to right, rather than shortcutting the entire false branch when a condition is true.
An example from the PHP manual explains this more clearly:
// on first glance, the following appears to output 'true'
echo (true?'true':false?'t':'f');
// however, the actual output of the above is 't'
// this is because ternary expressions are evaluated from left to right
// the following is a more obvious version of the same code as above
echo ((true ? 'true' : false) ? 't' : 'f');
// here, you can see that the first expression is evaluated to 'true', which
// in turn evaluates to (bool)true, thus returning the true branch of the
// second ternary expression.