Does there exist a travelling salesman problem where the optimal solution has edges that cross?
The nodes are in an x-y plane, so crossing in this case means if you wer
If you consider a non-Euclidean metric like L1 (Manhattan distance), then it's pretty easy to construct shortest tours that self-intersect.
+--3--+
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2--+--1
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+--4--+
If each neighboring pair of intersections is at distance 1, then all tours have length 8, including the self-intersecting one that goes 1 --> 2 --> 3 --> 4 --> 1.