Java 8 lambda expression with an abstract class having only one method [duplicate]

Answer 1

You can only instantiate a functional interface with a lambda expression.

For example:

If you change ClassA to be an interface (you'd probably want to rename it):

public interface ClassA {
    public abstract void action();
}

and keep ClassB as is:

public class ClassB {
   public ClassB(String text, ClassA a){
      //Do stuff
    }
}

You can pass an instance of (the interface) ClassA to the ClassB constructor with:

ClassB b = new ClassB("Example", () -> System.out.println("Hello"));    

On the other hand, your

ClassB b = new ClassB("Example", new ClassA(() -> System.out.println("Hello")));

attempt fails due to several reasons:

1. You can't instantiate an abstract class (you can only instantiate sub-classes of that class).
2. Even if you could instantiate class ClassA (if it wasn't abstract), your ClassA has no constructor that takes some functional interface as an argument, so you can't pass () -> System.out.println("Hello") as an argument to ClassA's constructor.