Rabbitmq retrieve multiple messages using single synchronous call

Question

Is there a way to receive multiple message using a single synchronous call ?

When I know that there are N messages( N could be a small value less than 10) in the queue,

Answer 1

First declare instance of QueueingBasicConsumer() wich wraps the model.
From the model execute model.BasicConsume(QueueName, false, consumer)
Then implement a loop that will loop around messages from the queue which will then processing
Next line - consumer.Queue.Dequeue() method - waiting for the message to be received from the queue.
Then convert byte array to a string and display it.
Model.BasicAck() - release message from the queue to receive next message
And then on the server side can start waiting for the next message to come through:

  public string GetMessagesByQueue(string QueueName)
    {
        var consumer = new QueueingBasicConsumer(_model);
        _model.BasicConsume(QueueName, false, consumer);

        string message = string.Empty;

        while (Enabled)
        {
            //Get next message
            var deliveryArgs = (BasicDeliverEventArgs)consumer.Queue.Dequeue();

            //Serialize message
             message = Encoding.Default.GetString(deliveryArgs.Body);
                _model.BasicAck(deliveryArgs.DeliveryTag, false);
        }
        return message;
    }