Comparing typenames in C++

Question

I typed this into a template function, just to see if it would work:

if (T==int)

and the intellisense didn\'t complain. Is this valid C++? What

Answer 1

Just to fit your requirement you should use typeid operator. Then your expression would look like

if (typeid(T) == typeid(int)) {
    ...
}

Obvious sample to illustrate that this really works:

#include 
#include 

template 
class AClass {
public:
    static bool compare() {
        return (typeid(T) == typeid(int));
    }
};

void main() {
    std::cout << AClass::compare() << std::endl;
    std::cout << AClass::compare() << std::endl;
}

So in stdout you'll probably get:

0
1