How does Optional covariance work in Swift

Question

How does covariance work for Optionals in Swift?

Say I write the following code:

var nativeOptionalView: Optional
let button =         


        

Answer 1

It doesn't. Swift does not support custom covariant generics for now.

The Swift type checker is per expression, not global (as in Haskell). This task is handled by the Semantic Analysis in lib/Sema. The constraint system then tries to match the types and special cases of covariance are then handled for collections, and optionals.

This was a language design decision. You should be able to do everything you need with the built-in collection types and optionals. If you aren't you should probably open a radar.