How is inheritance implemented at the memory level?

Question

Suppose I have

class A           { public: void print(){cout<<\"A\"; }};
class B: public A { public: void print(){cout<<\"B\"; }};
class C: public A         


        

Answer 1

There will not be any information stored in a object to describe a member function.

aobject.print();
bobject.print();
cobject.print();

The compiler will just convert the above statements to direct call to function print, essentially nothing is stored in a object.

pseudo assembly instruction will be like below

00B5A2C3   call        print(006de180)

Since print is member function you would have an additional parameter; this pointer. That will be passes as just every other argument to the function.