I noticed that tuple.productIterator
always returns an Iterator[Any]
an wondered if it\'s not possible to set multiple lower bounds (so it could be an
For the simple case where A
and B
are bound by the compiler as the same time as T
, IttayD's answer works fine:
def f[T, A <: T,B <: T](a:A, b:B) = List[T](a,b)
When A
and B
are already bound as in your class Foo[A, B]
example, you need to introduce temporary dummy variables to have the compiler do this job:
class Foo[A, B](a: A, b: B) {
def g[T, A1 >: A <: T, B1 >: B <: T] = List[T](a: A1, b: B1)
}
(For the sake of clarity: A1 >: A <: T
means that type A1
must be a supertype of A
and a subtype of T
, and not that A
is a subtype of both A1
and T
.)
A1
and B1
are here for the sole purpose of inferring a correct type for T
. If the compiler has to infer them, they will resolve to A1 = A
and B1 = B
, and then T
as the most specific type which is a superclass of both A
and B
.
One thing that the compiler doesn't realize, though, is that, by transitivity, we have both T >: A
and T >: B
, which follows directly from the constraints with respect to A1
and B1
. We need to help out with the type ascriptions.
Now, Product#productIterator
could not use this technique, as it's defined in a place where we don't even know A
and B
, or indeed how many type parameters there are in the concrete subclass.