Sort a sublist of elements in a list leaving the rest in place

Question

Say I have a sorted list of strings as in:

[\'A\', \'B\' , \'B1\', \'B11\', \'B2\', \'B21\', \'B22\', \'C\', \'C1\', \'C11\', \'C2\']

Now I wan

Answer 1

import re
from collections import OrderedDict

a = ['A', 'B' , 'B1', 'B11', 'B2', 'B21', 'B22', 'C', 'C1', 'C11', 'C2']
dict = OrderedDict()

def get_str(item):
  _str = list(map(str, re.findall(r"[A-Za-z]", item)))
  return _str

def get_digit(item):
  _digit = list(map(int, re.findall(r"\d+", item)))
  return _digit

for item in a:
  _str = get_str(item)
  dict[_str[0]] = sorted([get_digit(dig) for dig in a if _str[0] in dig])

nested_result = [[("{0}{1}".format(k,v[0]) if v else k) for v in dict[k]] for k in dict.keys()]
print (nested_result)
# >>> [['A'], ['B', 'B1', 'B2', 'B11', 'B21', 'B22'], ['C', 'C1', 'C2', 'C11']]

result = []
for k in dict.keys():
  for v in dict[k]:
    result.append("{0}{1}".format(k,v[0]) if v else k)
print (result)
# >>> ['A', 'B', 'B1', 'B2', 'B11', 'B21', 'B22', 'C', 'C1', 'C2', 'C11']