Simplest way to calculate amount of even numbers in given range

Question

What is the simplest way to calculate the amount of even numbers in a range of unsigned integers?

An example: if range is [0...4] then the answer is 3 (0,2,4)

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Answer 1

int start, stop;
start = 0;
stop = 9;
printf("%d",(stop-start)/2+((!(start%2) || !(stop%2)) ? 1 : 0));

Where start and stop can hold any value. No need to iterate to to determine this number.