MySQL LIKE + php sprintf

Question

$test = sprintf(\"SELECT * FROM `table` WHERE `text` LIKE \'%%s%\'\", mysql_real_escape_string(\'test\'));

echo $test;

output:

SELECT          


        

Answer 1

... LIKE '%%%s%%'", mysql_real_escape_string('test'));

To print the % character you need to escape it with itself. Therefore the first two %% will print the % character, while the third one is for the type specifier %s. You need a double %% at the end as well.