The shortest way to convert infix expressions to postfix (RPN) in C

Question

Original formulation is given here (you can try also your program for correctness) .

Additional rules:
1. The program should read from standard input and write to s

Answer 1

Here's a way to reduce the code down to 76 chars:

main(c){read(0,&c,1)?c-41&&main(c-40&&putchar(c,c%96>26&&main(c))):exit(0);}

A longer, commented version for clarity:

int main(int c)
{
   if (read(0,&c,1)) {          /* read char */
       if (c-41) {              /* if not ')' */
           if (c-40) {          /* then if not '(' */
               if (c%96>26) {   /* then if operator (not alphabet or ) */
                   main(c);     /* recurse */
               }
               putchar(c);      /* print */
           }
           main(c);             /* recurse */
       }        
   } else exit(0);              /* end program */
}