Why are JavaScript Arguments objects mutated by assignment to parameter?

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被撕碎了的回忆
被撕碎了的回忆 2021-02-13 11:15

What is the rationale behind this behaviour?

function f(x) {
  console.log(arguments[0]);
  x = 42;
  console.log(arguments[0]);
}

f(1);
// => 1
// => 42
         


        
2条回答
  •  无人共我
    2021-02-13 12:03

    Actually, in strict mode, this does not happen as you can see here.

    If you read section 10.6 of the ECMA Standard, in particular Note 1, you'll see:

    For non-strict mode functions the array index (defined in 15.4) named data properties of an arguments object whose numeric name values are less than the number of formal parameters of the corresponding function object initially share their values with the corresponding argument bindings in the function‘s execution context. This means that changing the property changes the corresponding value of the argument binding and vice-versa. This correspondence is broken if such a property is deleted and then redefined or if the property is changed into an accessor property. For strict mode functions, the values of the arguments object‘s properties are simply a copy of the arguments passed to the function and there is no dynamic linkage between the property values and the formal parameter values.

    In short, what this is saying is that, in non-strict mode, named function parameters operate as aliases for items in the arguments object. Thus, changing the value of a named parameter will change the value of the equivalent arguments item and vice versa. This is not a mistake. This is expected behaviour.

    As an editorial, it's probably not a good idea to rely on this behaviour as it can lead to some very confusing code. Also, such code, if executed in strict mode, would not longer work.

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