Produce std::tuple of same type in compile time given its length by a template argument

Question

In c++, how can I implement a function with an int template argument indicating the tuple length and produce a std::tuple with that length?

E.g.

func<         


        

Answer 1

If you're okay with a C++14 solution, Ryan's answer is the way to go.

With C++11, you can do the following (still based on index_sequence, but that's implementable in C++11):

template >
struct n_tuple;

template 
struct n_tuple> {
    template 
    using ignore = T;

    using type = std::tuple...>;
};

template 
using n_tuple_t = typename n_tuple::type;

With that:

template 
n_tuple_t func() {
    return n_tuple_t{};
}