In Lua, how can you print the name of the current function, like the C99 __func__ identifier?

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别那么骄傲
别那么骄傲 2021-02-13 03:49

Something like this:

function foo()
    print( __func__ )
   ...
end

How can it be done?

7条回答
  •  一向
    一向 (楼主)
    2021-02-13 04:29

    You can try:

    local dbFunc = debug.getinfo(1) and debug.getinfo(1).name or ""
    
    Info
    Info["currentline"] = 1376
    Info["source"] = "@.\mymod.lua"
    Info["short_src"] = ".\mymod.lua"
    Info["nups"] = 13
    Info["isvararg"] = false
    Info["what"] = "Lua"
    Info["lastlinedefined"] = 1570
    Info["func"] = function: 000000000030B440
    Info["istailcall"] = false
    Info["linedefined"] = 1375
    Info["namewhat"] = "field"
    Info["name"] = "ExportDB" <<--- See here the function name
    Info["nparams"] = 4
    

    debug.getinfo(1) Returns this structure of the current execution state of the active function in the stack.

    If n is larger than the number of active functions in the stack, debug.getinfo() returns nil.

    That's why you have to check if it exists before taking *.name and return an empty string if the information is not available

    A it is called inside the ExportDB() function, it return its name

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