org.hibernate.PersistentObjectException: detached entity passed to persist exception

Question

I\'m creating a simple app to just insert a row to a table (if table does not exist, create it) using Java JPA.

I\'m attaching some code for a runnable exam

Answer 1

Try with the below code then, it will allow you to set the ID manually.

Just use the @Id annotation which lets you define which property is the identifier of your entity. You don't need to use the @GeneratedValue annotation if you do not want hibernate to generate this property for you.

assigned - lets the application to assign an identifier to the object before save() is called. This is the default strategy if no element is specified.

package view;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name = "People")
public class Person {
    @Id
    //@GeneratedValue(strategy = GenerationType.AUTO) // commented for manually set the id
    private int id;

    private String name;
    private String lastName;

    public Person(int id, String name, String lastName) {
        this.id = id;
        this.name = name;
        this.lastName = lastName;
    }

    public Person() {
    }
}