C++ standard: can relaxed atomic stores be lifted above a mutex lock?

前端 未结 2 1309
予麋鹿
予麋鹿 2021-02-13 00:54

Is there any wording in the standard that guarantees that relaxed stores to atomics won\'t be lifted above the locking of a mutex? If not, is there any wording that explicitly s

2条回答
  •  小蘑菇
    小蘑菇 (楼主)
    2021-02-13 01:32

    No memory operation inside a mutex protected region can 'escape' from that area. That applies to all memory operations, atomic and non-atomic.

    In section 1.10.1:

    a call that acquires a mutex will perform an acquire operation on the locations comprising the mutex Correspondingly, a call that releases the same mutex will perform a release operation on those same locations

    Furthermore, in section 1.10.1.6:

    All operations on a given mutex occur in a single total order. Each mutex acquisition “reads the value written” by the last mutex release.

    And in 30.4.3.1

    A mutex object facilitates protection against data races and allows safe synchronization of data between execution agents

    This means, acquiring (locking) a mutex sets a one-way barrier that prevents operations that are sequenced after the acquire (inside the protected area) from moving up across the mutex lock.

    Releasing (unlocking) a mutex sets a one-way barrier that prevents operations that are sequenced before the release (inside the protected area) from moving down across the mutex unlock.

    In addition, memory operations that are released by a mutex are synchronized (visible) with another thread that acquires the same mutex.

    In your example, foo_has_been_set is checked in CheckFoo.. If it reads true you know that the value 1 has been assigned to foo by SetFoo, but it is not synchronized yet. The mutex lock that follows will acquire foo, synchronization is complete and the assert cannot fire.

提交回复
热议问题